Javascript Comparing Two Arrays of Objects

Comparing Two Arrays of Objects and remove duplicates

If you want to compare two array of objects and filter out the duplicates and return only the unique values from the second array. You can use the following snippet. If it is other way and you want to get only the common values just remove the ! from the filter function.

let firstArray = [
    {name: "A", valueOne: 10, valueTwo: 15},
    {name: "B", valueOne: 7, valueTwo: 3},
    {name: "C", valueOne: 11, valueTwo: 12}
]
let secondArray = [
    {name: "D", valueOne: 5, valueTwo: 1},
    {name: "E", valueOne: 2, valueTwo: 23},
    {name: "C", valueOne: 9, valueTwo: 17},
    {name: "B", valueOne: 1, valueTwo: 19},
    {name: "A", valueOne: 30, valueTwo: 20}
]
const newArray = secondArray.filter(({ name }) => !firstArray.some((e) => e.name === name))
console.log(newArray) // [
							  { name: 'D', valueOne: 5, valueTwo: 1 },
							  { name: 'E', valueOne: 2, valueTwo: 23 }
						  ]

let a = [{'name':'bob', 'age':22}, {'name':'alice', 'age':12}, {'name':'mike', 'age':13}];
let b = [{'name':'bob', 'age':62}, {'name':'kevin', 'age':32}, {'name':'alice', 'age':32}];
const result = b.filter(({ name }) => !a.some((e) => e.name === name))
console.log(result) // [ { name: 'kevin', age: 32 } ]